[Figure: FiveStudy logo]
FiveStudy
Calculus BC · Unit 3 · 3.5
AP Calculus · Differentiation: Composite, Implicit, and Inverse Functions
Selecting Procedures for Calculating Derivatives
No new rules. The skill is naming the outermost operation before you differentiate anything.
key idea$\text{Read the STRUCTURE before you differentiate anything}$
How to choose
No new technique appears here. What is tested is whether you can look at an expression and name its top-level structure — because the outermost operation decides which rule leads, and everything else nests inside it.
| Step | What you do | Why it comes first |
|---|
| 1 | Ask: can this be simplified first? | expanding or dividing often removes the need for any rule |
| 2 | Identify the last operation you would perform to evaluate it | that operation is the outermost, and its rule leads |
| 3 | Apply that rule, treating the parts as black boxes | keeps the structure intact while you work |
| 4 | Recurse into each part | inner structures get their own rules |
Step 2 is the whole skill. “What would I do last if I were plugging in a number?” identifies the outer operation every time.
The decision tree
Simplify if you can. Then find the outermost operation below.
SIMPLIFY?The expression divides, expands or cancels.Do that first. $\dfrac{x^{3}+2x}{x}$ is $x^{2}+2$; $x^{2}\cdot x^{5}$ is $x^{7}$. A rule applied to an unsimplified expression is correct but slow and error-prone.
OUTER = $+$ or $-$Terms joined at the top level.Split. Differentiate each term independently — linearity. Then recurse into each one.
OUTER = $\times$Two functions multiplied, neither constant.Product rule. $f'g+fg'$. If one factor is a constant, it is a constant multiple instead, not a product.
OUTER = $\div$One function over another, denominator not constant.Quotient rule — or rewrite as a product with a negative exponent if that is cleaner.
OUTER = compositionA function inside another: brackets, roots, exponents, trig arguments.Chain rule. Differentiate outer, keep the inside, multiply by the inner derivative.
OUTER = an equation in $x$ and $y$$y$ cannot be isolated.Implicit differentiation. Differentiate both sides; every $y$ carries $\tfrac{dy}{dx}$.
| Expression | Outermost operation | Leading rule |
|---|
| $x^{2}\sin x$ | multiplication | product |
| $\sin\left(x^{2}\right)$ | composition | chain |
| $\dfrac{\sin x}{x^{2}}$ | division | quotient |
| $x^{2}+\sin x$ | addition | split, then basic rules |
| $\left(x^{2}\sin x\right)^{4}$ | composition | chain, then product inside |
| $\dfrac{x^{2}+x}{x}$ | — | simplify first → $x+1$ |
Rows 1–3 use the same two functions and need three different rules. The operation joining them is the only thing that changed.
Worked examples
EX 1
Same pieces, three different rules
discriminationDifferentiate $x^{2}\sin x$, $\sin\left(x^{2}\right)$ and $\dfrac{x^{2}}{\sin x}$.
1
First: multiplication
Product rule: $2x\sin x+x^{2}\cos x$.
2
Second: composition
Chain rule with inner $x^{2}$: $\cos\left(x^{2}\right)\cdot2x=2x\cos\left(x^{2}\right)$.
3
Third: division
Quotient rule: $\dfrac{2x\sin x-x^{2}\cos x}{\sin^{2}x}$.
4
Compare
Identical ingredients, three unrelated answers. The joining operation did all the work.
5
The habit
Before differentiating, say out loud which operation is outermost. That one sentence prevents most errors on this topic.
EX 2
Nested structures
$\left(x^{2}\sin x\right)^{4}$Differentiate $y=\left(x^{2}\sin x\right)^{4}$.
1
Outermost first
The last operation is raising to the 4th power — a composition, so the chain rule leads.
2
Apply it, treating the inside as a black box
$y'=4\left(x^{2}\sin x\right)^{3}\cdot\dfrac{d}{dx}\left[x^{2}\sin x\right]$.
3
Now recurse
The inside is a product: $\dfrac{d}{dx}\left[x^{2}\sin x\right]=2x\sin x+x^{2}\cos x$.
4
Assemble
$y'=4\left(x^{2}\sin x\right)^{3}\left(2x\sin x+x^{2}\cos x\right)$.
5
Note the order
Chain outside, product inside. Reversing them produces nonsense.
EX 3
The one that needs no rule
$\dfrac{x^{3}-x}{x}$Differentiate $y=\dfrac{x^{3}-x}{x}$.
1
Check for simplification
The denominator is a single power and the numerator is a sum, so division distributes.
2
Simplify
$y=x^{2}-1$ for $x\neq0$.
4
Compare the alternative
The quotient rule gives $\dfrac{\left(3x^{2}-1\right)x-\left(x^{3}-x\right)}{x^{2}}=\dfrac{2x^{3}}{x^{2}}=2x$ — same answer, four times the work.
5
Why step 1 exists
Checking for a simplification costs five seconds and sometimes saves the entire problem.
EX 4
Constant multiple, not a product
$5\cos x$A student applies the product rule to $y=5\cos x$, getting $0\cdot\cos x+5\cdot(-\sin x)$. Comment.
1
Check the answer
It simplifies to $-5\sin x$, which is correct.
2
Check the classification
$5$ is a constant, not a function of $x$, so this is a constant multiple, not a product.
3
Note what the product rule did
It handled the case correctly because $\tfrac{d}{dx}[5]=0$ kills the extra term. The rule is not wrong, just unnecessary.
4
Give the direct route
Constant multiple rule: $5\cdot\dfrac{d}{dx}[\cos x]=-5\sin x$.
5
The discriminator
A product needs both factors to depend on $x$. If one is a number, pull it out and move on.
EX 5
When $y$ will not isolate
$x^{2}y+\sin y=4$Which technique differentiates $x^{2}y+\sin y=4$, and what is the first line?
1
Try to isolate $y$
$x^{2}y+\sin y=4$ mixes $y$ algebraically and inside a trig function. No rearrangement isolates it.
2
Choose the technique
Implicit differentiation — differentiate both sides as they stand.
3
Handle each term
$x^{2}y$ is a product: $2xy+x^{2}\dfrac{dy}{dx}$. $\sin y$ is a composition: $\cos y\dfrac{dy}{dx}$. The constant gives $0$.
4
Write the first line
$2xy+x^{2}\dfrac{dy}{dx}+\cos y\dfrac{dy}{dx}=0$.
5
Note the nesting
Implicit differentiation is the outer decision; product and chain rules operate inside it. The routing question is answered before any rule is applied.
Watch out
Differentiating before reading the structure
Most errors on this topic are a correct rule applied to the wrong level. Name the outermost operation first, every time.
Skipping the simplification check
$\dfrac{x^{3}-x}{x}$ and $x^{2}\cdot x^{5}$ need no rule at all. Five seconds of inspection saves minutes.
A constant factor is not a product
$5\cos x$ needs the constant multiple rule. Using the product rule works but signals you have not read the structure.
Rules nest, they do not compete
$\left(x^{2}\sin x\right)^{4}$ needs chain and product, in that order. Asking “which rule?” as though only one applies is the wrong question.